Question
Factorize:
$64a^3 + 125b^3 + 240a^2b + 300ab^2$

Answer

$64 a^3+125 b^3+240 a^2 b+300 a b^2$
$=(4 a)^3+(5 b)^3+3 \times(4 a)^2 \times 5 b+3(4 a)(5 b)^2$
$=(4 a+5 b)^3\left[\because a^3+b^3+3 a^2 b+3 a b^2=(a+b)^3\right]$
$=(4 a+5 b)(4 a+5 b)(4 a+5 b)$
$\therefore 64 a^3+125 b^3+240 a^2 b+300 a b^2$
$=(4 a+5 b)(4 a+5 b)(4 a+5 b)$

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