Question
Factorize of the following expressions: $16(a - b)^3- 24 (a - b)^2$
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Answer
$16(a-b)^3-24(a-b)^2$
$=8(a-b)^2[2(a-b)-3]\left[\right.$ taking $8(a-b)^2$ as the common factor$]$
$=8(a-b)^2(2 a-2 b-3)$
$=8(a-b)^2[2(a-b)-3]\left[\right.$ taking $8(a-b)^2$ as the common factor$]$
$=8(a-b)^2(2 a-2 b-3)$
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