Question
Factorize of the following expressions: $a(a - 2b - c) + 2bc$
✓
Answer
$a(a - 2b - c) + 2bc= a^2- 2ab - ac + 2bc$
$= (a^2- ac) + (2bc - 2ab)$
$= a(a - c) + 2b(c - a) $[since, $(9c - a)= -(a - c)]$
$= a(a - c) - 2b(a - c)$
$= (a - 2b)(a - c)$ [taking $(a - c)$ as the common factor]
$= (a^2- ac) + (2bc - 2ab)$
$= a(a - c) + 2b(c - a) $[since, $(9c - a)= -(a - c)]$
$= a(a - c) - 2b(a - c)$
$= (a - 2b)(a - c)$ [taking $(a - c)$ as the common factor]
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