Question
Which is largest in $6\frac{2}{3}\%,\frac{3}{20}$ and $0.14?$
✓
Answer
We may write, $6\frac{2}{3}\%=\frac{20}{3}\%=\Big(\frac{20}{3}\times\frac{1}{100}\Big)=\frac{1}{15}=0.067$
$\frac{3}{20}=-0.15$ and third number is $0.14$ clearly $0.15$ is the largest hence $\frac{3}{20}$ is largest.
$\frac{3}{20}=-0.15$ and third number is $0.14$ clearly $0.15$ is the largest hence $\frac{3}{20}$ is largest.
Need a full question paper?
Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.
Explore more
Similar questions
Find the cube roots of the following numbers by successive subtraction of numbers: $1, 7, 19, 37, 61, 91, 127, 169, 217, 271, 331, 397, ...1728$
→Find the surface area of a cube whosevolume is:
$216\ dm^3$
→$216\ dm^3$
Find the selling price when. $CP = Rs. 1650$ and gain $\% = 4\%$
→Find the volume of a cube whose surface area is $384m^2$.
→Expand the following, using suitable identities.$\Big(\frac{2\text{a}}{3}+\frac{\text{b}}{3}\Big)\Big(\frac{2\text{a}}{3}-\frac{\text{b}}{3}\Big)$
→Factorize: $a x^2 y+b x y^2+c x y z$
→Why is it incorrect to call the solid shown here a cylinder?
Find the least number that must be added to $1300$ so as to get a perfect square. Also find the square root of the perfect square.
→Factorise the following, using the identity $a^2+2 a b+b^2=(a+b)^2$
$\frac{\text{x}^2}{4}+2\text{x}+4$
→$\frac{\text{x}^2}{4}+2\text{x}+4$
Three coins are tossed together. Find the probability of getting: at least two heads.