Question
Factorize the following expressions:
$x^4y^4 - xy$

Answer

$x^4 y^4-x y \\$
$=x y\left(x^3 y^3-1\right) \\$
$=x y\left((x y)^3-1^3\right) \\$
$=x y(x y-1)\left((x y)^2+x y \times 1+12\right) \\ {\left[\therefore x^3-y^3=(x-y)\left(x^2+x y+y^2\right)\right]} \\$
$=x y(x y-1)\left(x^2 y^2+x y+1\right) \\$
$\therefore x^4 y^4-x y=x y(x y-1)\left(x^2 y^2+x y+1\right)$

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