Question
Water in a rectangular reservoir having base $80\ m$ by $60\ m$ is $6.5\ m$ deep. In what time can the water be pumped by a pipe of which the cross-section is a square of side $20\ cm$ if the water runs through the pipe at the rate of $15\ km/hr.$

Answer

Flow of water $= 15\ km/hr$
$= 15000\ m/hr$ Volume of water coming out of the pipe in one hour,
$\Rightarrow\frac{20}{100}\times\frac{20}{100}\times15000=600\text {m}^3$
Volume of the tank $= 80 \times 60 \times 6.5 = 31200m^3$
Times taken to empty the tank $=\frac{\text{Volume of tank}}{\text{Volume of water coming out of pipe in one hour}}$
$=\frac{31200}{600}=52\text{ hours}$

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