Question
Factorize:
x3 - 12x(x - 4) - 64

Answer

x3 - 12x(x - 4) - 64

x3 - 12x2 + 48x - 64

= (x)3 - 3 × x2 × 4 + 3 × 42 × x - 43 $\big[\because$ a3 - 3a2b + 3ab2 - b3= (a - b)3$\big]$

= (x - 4)(x - 4)(x - 4)

$\therefore$ x3 - 12x(x - 4) - 64

= (x - 4)(x - 4)(x - 4)

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