Question
Factorize: $x^3-2 x^2-x+2$

Answer

$x^3-2 x^2-x+2$
We need to consider the factors of $2 ,$ which are $\pm 1, \pm 2$
Let us substitute $1$ in the polynomial $x^3-2 x^2-x+2$ to get
$(1)^3-2(1)^2-(1)+2=1-2-1+2=0$
Thus, according to factor theorem, we can conclude that $(x-1)$ is a factor of the polynomial
$x^3-2 x^2-x+2$
Let us divide the polynomial $x^3-2 x^2-x+2$ by $(x-1)$,to get
Image
$x^3-2 x^2-x+2$
$=(x-1)\left(x^2-x-2\right) .$
$=(x-1)\left(x^2+x-2 x-2\right)$
$=(x-1)[x(x+1)-2(x+1)]$
$=(x-1)(x-2)(x+1) .$
Therefore, we can conclude that on factorizing the polynomial $x^3-2 x^2-x+2$,
we get $(x-1)(x-2)(x+1)$

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