In simple harmonic motion, acceleration $\quad a=-\omega^2 x\quad\quad...(1)$ $\quad$$\quad$(where $\omega$ is constant) and velocity $\quad v=\frac{d x}{d t}\quad\quad...(2)$ (i) When $t=0.3$ $sec$ and $x$ is negative. The slope of the $x-t$ graph is negative from which $v$ is also negative. From equation (1) the acceleration a is positive. (ii) When $t =1.2$ $sec$ then $x$ is positive. The slope of the $x-t$ graph is positive from which $v$ is also positive. From equation (1) the acceleration a is negative. (iii) when $t =-1.2$ $sec$ them $x$ is negative. The slope of the $x-t$ graph is positive so that $v$ is positive. From equation (1) the acceleration $a$ is positive.
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