Figure, shows a person standing somewhere in between two identica… - Vidyadip

Question

Figure, shows a person standing somewhere in between two identical tuning forks, each vibrating at 512Hz. If both the tuning fbrks move towards right at a speed of 5.5m/s, find the number of beats heard by the listener. Speed of sound in air = 330m/s.

✓

Answer

According to the data, V_s = 5.5m/s for each turning fork.

So, the apparent frequency heard from the tuning fork on the left,

$\text{f}'=\Big(\frac{330}{330-5.5}\Big)\times512=527.36\text{Hz}=527.5\text{Hz}$

Similarly, apparent frequency from the tunning fork on the right,

$\text{f}'=\Big(\frac{330}{330-5.5}\Big)\times512=510\text{Hz}$

So, beats produced $527.5-510=17.5\text{Hz}.$

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