Figure shows a solid hemisphere with a charge of $5\ nC$ distributed uniformly through its volume. The hemisphere lies on a plane and point $P$ is located on this plane, along a radial line from the centre of curvature at distance $15\ cm$. The electric potential at point $P$ due to the hemisphere, is .....$V$
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Total charge $=\mathrm{5\;nc}=5 \times 10^{-9} \mathrm{\,c}$

${V=\frac{K q}{r}=\frac{9 \times 10^{9} \times 5 \times 10^{-9}}{15 \times 10^{-2}}} $

${V=300 \mathrm{\,V}}$

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