Figure shows a square current carrying loop $ABCD$ of side $10\,\, cm$ and current $i = 10\,A$. The magnetic moment $\vec M$ of the loop is
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Areal vects will be $\perp$ to the plane Area vec-tors is at $60^{\circ}$ angle with axis and $30^{\circ}$ angle with $-z$ axis

$\vec{M}=N I \vec{A}$

$\vec{M}=10 \times 10^{-2} \mathrm{Amp}-\mathrm{m}^{2}$

$M=0.1 A m p-m^{2}$

$\vec{M}=M x \hat{i}-M y \hat{k}=M \cos 60 \hat{i}-M \cos 30^{\circ} \hat{k}$

$\vec{M}=0.05(\hat{i}-\sqrt{3} \hat{k})$

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