Question
Write a pythagorean triplet whose smallest member is:
$6$

Answer

For every natural number $m>1,\left(2 m, m^2-1, m^2+1\right)$ is a Pythagorean triplet.

Putting $2 m=6$

We get $m =3$

Thus, we get the triplet $(6,8,10)$.

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