Question
Fill in the blank.$\Big(\frac{-2}{3}\Big)^{-2}=\ ......$

Answer

$\Big(\frac{-2}{3}\Big)^{-2}=\frac{9}{4}$Solution:
$\Big(\frac{-2}{3}\Big)^{-2}$
$=\Big(\frac{3}{-2}\Big)^{2}$
$=\frac{3^2}{-2^2}$
$=\frac{9}{4}$

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