Question
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Answer
$144\times2^{-3}=144\times\frac{1}{8}=18$
$18\times12^{-1}=18\times\frac{1}{12}=\frac{3}{2}$
$\frac{3}{2}\times3^{-2}=\frac{3}{2}\times\frac{1}{3^{2}}=\frac{1}{2\times3}=\frac{1}{6}$
$18\times12^{-1}=18\times\frac{1}{12}=\frac{3}{2}$
$\frac{3}{2}\times3^{-2}=\frac{3}{2}\times\frac{1}{3^{2}}=\frac{1}{2\times3}=\frac{1}{6}$
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