Question
How many non-perfect square natural numbers lie between $18^2$ and $19^2?$
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Answer
We know that there are $2 \text{n}$ non-perfect square numbers between two consecutive square numbers $\text{n}^2$ and $(\text{n}+1)^2$.
Here, $18^2=324$ and $19^2=361$ and $2 \text{n}=2 \times 18$
So, there are 36 non-perfect square numbers between 324 and 361.
Here, $18^2=324$ and $19^2=361$ and $2 \text{n}=2 \times 18$
So, there are 36 non-perfect square numbers between 324 and 361.
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