MCQ
Final product $'C'$ is ?


- ✓

- B

- C

- D







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$C{H_3} - \mathop {\mathop {CH - }\limits_{|\,\,\,\,\,\,\,} }\limits_{C{H_3}\,} C{H_2} - C{H_2} - Cl$
$(1)$ $(CH_3)_3 {\bar{\ddot{C}}}$
$(2)$ ${(C{H_3})_2}{\bar {\ddot {CH}}}$
$(3) $ $C{H_3}{\bar{\ddot{C{H_2}}}}$
$(4)$ ${C_6}{H_5}{\bar{\ddot{C{H_2}}}}$ is
