Question
Find$: \text{AC}$
✓
Answer
From right triangle $\text{ABC}$
$\sin B=\frac{AB}{A C} $
$ \sin 30^{\circ}=\frac{A B}{A C} $
$ \frac{1}{2}=\frac{12}{A C} $
$\text{AC}=24\ cm$
$\sin B=\frac{AB}{A C} $
$ \sin 30^{\circ}=\frac{A B}{A C} $
$ \frac{1}{2}=\frac{12}{A C} $
$\text{AC}=24\ cm$
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