Question
Find all pairs of consecutive odd natural number, both of which are larger than 10, such that their sum is less than 40.

Answer

Let x be the smaller of the two consecutive odd natural numbers. Then the other odd integer is x+2.
It is given that both the natural number are greater than 10 and their sum is less than 40.
$\therefore$ x > 10 and, x + x + 2 < 40
$\Rightarrow$ x > 10 and 2x < 38
$\Rightarrow$ x > 10 and x <19
$\Rightarrow$ 10 < x < 19
$\Rightarrow$ x = 11,13,15,17 [$\because$ x is an odd number]
Hence, the required pairs of odd natural number are (11, 13), (13, 15), (15, 17) and (17, 19).

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