Question
Find at least $3$ solutions for the linear equation $2x – 3y + 7 = 0.$

Answer

$2 x-3 y+7=0$
$\Rightarrow 3 y=2 x+7$
$\Rightarrow y=\frac{2 x+7}{3}$
Put $x =0$, then $y=\frac{2(0)+7}{3}=\frac{7}{3}$
Put $x =1$, then $y=\frac{2(1)+7}{3}=3$
Put $x =2$, then $y=\frac{2(2)+7}{3}=\frac{11}{3}$
Put $x=3$, then $y=\frac{2(3)+7}{3}=\frac{13}{3}$
$\therefore\left(0, \frac{7}{3}\right),(1,3),\left(2, \frac{11}{3}\right)$ and $\left(3, \frac{13}{3}\right)$ are the solutions of the equation $2 x-3 y+7=0$.

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