Question
Find
$\frac{1}{4}$ of$\quad$(a) $\frac{1}{4}$ (b) $\frac{3}{5}$ (c) $\frac{4}{3}$
$\frac{1}{4}$ of$\quad$(a) $\frac{1}{4}$ (b) $\frac{3}{5}$ (c) $\frac{4}{3}$
✓
Answer
(a) We have, $\frac{1}{4}$ of $\frac{1}{4}=\frac{1}{4} \times \frac{1}{4}=\frac{1 \times 1}{4 \times 4}=\frac{1}{16}$
[ $\because$ 'of' means multiplication]
(b) We have, $\frac{1}{4}$ of $\frac{3}{5}=\frac{1}{4} \times \frac{3}{5}=\frac{1 \times 3}{4 \times 5}=\frac{3}{20}$
(c) We have, $\frac{1}{4}$ of $\frac{4}{3}=\frac{1}{4} \times \frac{4}{3}=\frac{1 \times 4}{4 \times 3}=\frac{4}{12}=\frac{1}{3}$
[dividing numerator and denominator by 4]
[ $\because$ 'of' means multiplication]
(b) We have, $\frac{1}{4}$ of $\frac{3}{5}=\frac{1}{4} \times \frac{3}{5}=\frac{1 \times 3}{4 \times 5}=\frac{3}{20}$
(c) We have, $\frac{1}{4}$ of $\frac{4}{3}=\frac{1}{4} \times \frac{4}{3}=\frac{1 \times 4}{4 \times 3}=\frac{4}{12}=\frac{1}{3}$
[dividing numerator and denominator by 4]
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