Question
Find
$\frac{7}{9}-\frac{2}{5}$
$\frac{7}{9}-\frac{2}{5}$
✓
Answer
Given, $\frac{7}{9}-\frac{2}{5}=\frac{7}{9}+$ Additive inverse of $\left(\frac{2}{5}\right)=\frac{7}{9}+\left(-\frac{2}{5}\right)$
$\because$ LCM of 9 and $5=45$
$
\therefore
\frac{7}{9}=\frac{7 \times 5}{9 \times 5}=\frac{35}{45}, \frac{-2}{5}=\frac{-2 \times 9}{5 \times 9}=\frac{-18}{45}
$
Now, $\frac{7}{9}-\frac{2}{5}=\frac{35}{45}+\left(\frac{-18}{45}\right)=\frac{35-18}{45}=\frac{17}{45}$
$\because$ LCM of 9 and $5=45$
$
\therefore
\frac{7}{9}=\frac{7 \times 5}{9 \times 5}=\frac{35}{45}, \frac{-2}{5}=\frac{-2 \times 9}{5 \times 9}=\frac{-18}{45}
$
Now, $\frac{7}{9}-\frac{2}{5}=\frac{35}{45}+\left(\frac{-18}{45}\right)=\frac{35-18}{45}=\frac{17}{45}$
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