Question
Find how many integers between $200$ and $500$ are divisible by $8.$
✓
Answer
The first number that is divisible by $8$ between $200$ and $500$ is $208$ and the last number that is divisible by $8$ are $496.$
So, the sequence will be $208,216,224.....496.$
Common difference $d=8$
First term $a=208$
Let there be $n$ terms is the sequence
Using the formula $a_n=a+(n-1) d$
Where $a_n=496, a=208$ and $d=8$$496=208+(n-1)(8)$
$(n-1) 8=288$
$n-1=36$
$n=37$
Hence, between $200$ and $500$ there are $37$ integers that are divisible by $8.$
So, the sequence will be $208,216,224.....496.$
Common difference $d=8$
First term $a=208$
Let there be $n$ terms is the sequence
Using the formula $a_n=a+(n-1) d$
Where $a_n=496, a=208$ and $d=8$$496=208+(n-1)(8)$
$(n-1) 8=288$
$n-1=36$
$n=37$
Hence, between $200$ and $500$ there are $37$ integers that are divisible by $8.$
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