Question
Find, if point (-5,0) lie on the line x – 2y + 5 = 0
✓
Answer
Substituting x = −5 and y = 0 in the given equation, we have:
L.H.S. = −5 − 2 × 0 + 5
= −5 − 0 + 5
= 5 − 5
= 0 = R.H.S.
Thus, the point (−5, 0) lie on the given line.
L.H.S. = −5 − 2 × 0 + 5
= −5 − 0 + 5
= 5 − 5
= 0 = R.H.S.
Thus, the point (−5, 0) lie on the given line.
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