Question
Find linear magnification in the given diagram.
✓
Answer
$\mathrm{m}_{1}=-\frac{\mathrm{f}}{\mathrm{x}_{1}}=\frac{-1}{49}$
$\mathrm{v}=\mathrm{m}_{1} \mathrm{u}=\frac{-1}{49} \times-50=1.02 \mathrm{\,m}=102 \mathrm{\,cm}$
first image will act as object for second lens
$\mathrm{u}=+12 \mathrm{\,cm}, \mathrm{f}=-8 \mathrm{\,cm}$
$\mathrm{m}_{2}=\frac{-8}{-8+12}=-2$
$\mathrm{m}=\mathrm{m}_{1} \times \mathrm{m}_{2}=-2 \times \frac{-1}{49}=0.04$
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