In the circuit shown, the power developed in the $6\,\Omega $ resistor is $6\,W.$ The power developed in the $4\,\Omega $ resistor is .............. $W$
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$P_{6}=I_{6}^{2} \times R \Rightarrow 6=I_{6}^{2} \times 6 \Rightarrow I_{6}=1$
$\mathrm{I}_{4} \times 4=1 \times 6 \Rightarrow \mathrm{I}_{4}=1.5$
$P_{4}=(1.5)^{2} \times 4=2.25 \times 4=9 \mathrm{\,W}$
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