Question
Find $n$ if ${ }^{2 n} C_{r-1}={ }^{2 n} C_{r+1}$

Answer

$
\begin{aligned}
& { }^{2 n} C_{r-1}={ }^{2 n} C_{r+1} \\
& \text { If }{ }^n C_x={ }^n C_y \text {, then either } x=y \text { or } x=n-y \\
& \therefore r-1=r+1 \text { or } r-1=2 n-(r+1)
\end{aligned}
$
But $r-1=r+1$ is not possible
$
\begin{aligned}
& \therefore \mathrm{r}-1=2 \mathrm{n}-(\mathrm{r}+1) \\
& \therefore \mathrm{r}+\mathrm{r}=2 \mathrm{n} \\
& \therefore \mathrm{r}=\mathrm{n}
\end{aligned}
$

Need a full question paper?

Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.

Start Generating Free