Find out equivalent capacitance between $A$ and $B$.
Diffcult
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Let $\mathrm{C}=\frac{\mathrm{A} \in_{0}}{\mathrm{d}} .$ Equivalent circuit
$\frac{1}{C_{e q}}=\frac{1}{C}+\frac{2}{3 C}=\frac{5}{3 C}$
${C_{eq}} = \frac{{3C}}{5} = \frac{{3A{ \in _0}}}{{5d}}$
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