
- A$A > B > C > D$
- ✓$B > C > D > A$
- C$D > C > B > A$
- D$B > D > C > A$

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$\mathop {\begin{array}{*{20}{c}}
{\,\,\,\,\,\,\,\,\,\,\,\,\,\,O}\\
{\,\,\,\,\,\,\,\,\,\,\,\,\,\,||}\\
{CH \equiv C - C - OH}
\end{array}}\limits_{\rm{I}} $ $\mathop {\begin{array}{*{20}{c}}
{\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,O}\\
{\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,||}\\
{C{H_2} = CH - C - OH}
\end{array}}\limits_{{\rm{II}}} $ $\mathop {\begin{array}{*{20}{c}}
{\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,O}\\
{\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,||}\\
{C{H_3} - C{H_2} - C - OH}
\end{array}}\limits_{{\rm{III}}} $$\mathop {\begin{array}{*{20}{c}}
\,\,\,{C{H_3}\,\,\,\,\,\,O}\\
\,\,\,{|\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,||}\\
{C{H_3} - CH - C - OH}
\end{array}}\limits_{{\rm{IV}}} $
$(A)$ Hydrolysis of Marshall's acid gives $H_2SO_4$ and $H_2O_2$ as final product
$(B)$ In $SCNSiH_3$ structure around $N$ is bent
$(C)$ Basic unit for silicates is $SiO_4^{-4}$
$(D)$$N{H_4}Cl + NaOH \to N{H_3} \uparrow $

In addition of $HOBr$ to $(I)$ and $(II)$
${\left( {I} \right)}$ ${{C_6}{H_5}COC{H_3}}$
${\left( {II} \right)}$ ${C{H_3}COC{H_3}}$
${\left( {III} \right)}$ ${C{H_3} - CHO}$
