MCQ
Find out the work done (in $ \times 10^{-3}\;J$) to expand the soap bubble to radius $R =5\, cm$ (Surface tension of water $=0.1\; N / m )$
- A$2.8$
- ✓$6.28$
- C$3.7$
- D$5.8$
$W=2\left(4 \pi R^{2}\right)(T)$ $...(I)$
Substitute $5 \times 10^{-2} m$ for $R$ and $0.1 N / m$ for $T$ in equation $(I).$
$W=2\left(4 \pi\left(5 \times 10^{-2} m \right)^{2}\right)(0.1 N / m )$
$=6.28 \times 10^{-3} J$
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