MCQ
Find potential at point $C$ and $D$
- A$V_C = 6\,V$ ; $V_D = 9\,V$
- ✓$V_C = 9\,V$ ; $V_D = 6\,V$
- C$V_C = -9\,V$ ; $V_D = -6\,V$
- D$V_C = -6\,V$ ; $V_D = -9\,V$
✓
Answer
Correct option: B.
$V_C = 9\,V$ ; $V_D = 6\,V$
b
$I=\frac{12-6}{3+3}=\frac{6}{6}=1 A$
$I=\frac{12-6}{3+3}=\frac{6}{6}=1 A$
$\frac{v_C-v_D}{3} =1$
$v_C=3+v_D=3+6$
$v_C=9\,V$
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