Question
Find six rational numbers between $\frac{-4}{8}\text{ and }\frac{3}{8}$
✓
Answer
We know that: $- 4, -3, -2, -1, 0, 1, 2, 3$
Therefore $\frac{-4}{8},\frac{-3}{8},\frac{-2}{8},\frac{-1}{8},\frac{0}{8},\frac{1}{8},\frac{2}{8},\frac{3}{8}$
Hence $6$ rational numbers between $\frac{-4}{8}$ and $\frac{3}{8}$ are $\frac{-3}{8},\frac{-2}{8},\frac{-1}{8},\frac{0}{8},\frac{1}{8},\frac{2}{8}$
Therefore $\frac{-4}{8},\frac{-3}{8},\frac{-2}{8},\frac{-1}{8},\frac{0}{8},\frac{1}{8},\frac{2}{8},\frac{3}{8}$
Hence $6$ rational numbers between $\frac{-4}{8}$ and $\frac{3}{8}$ are $\frac{-3}{8},\frac{-2}{8},\frac{-1}{8},\frac{0}{8},\frac{1}{8},\frac{2}{8}$
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