
$\Delta \mathrm{T}=100^\circ \mathrm{C}$
Expanding it on a plan
$\text { By symmetry } \quad \mathrm{T}_{\mathrm{H}}=\mathrm{T}_{\mathrm{B}}$
$\mathrm{T}_{\mathrm{C}}=\mathrm{T}_{\mathrm{E}}$
$\Rightarrow$ Points $\mathrm{B}$ and $\mathrm{H} \& \mathrm{E}$ and $\mathrm{C}$ coule
ai ned toget her.
olving it like normal current circuit
Temp. difference across $\mathrm{BC}$
$\frac{{{{100}^ \circ } - {0^ \circ }C}}{{\frac{{7R}}{2}}} \times \frac{{5R}}{2} = \frac{{100}}{7} \times 5 = \frac{{500}}{7}{\,^ \circ }C$