MCQ
Find Temperature difference between $B$ and $C$ ? (All rods are identical)


- A$\frac{{600}}{{13}}\ ^oC$
- ✓$\frac{{500}}{{7}}\ ^oC$
- C$\frac{{400}}{{13}}\ ^oC$
- D$\frac{{700}}{{6}}\ ^oC$

$\Delta \mathrm{T}=100^\circ \mathrm{C}$
Expanding it on a plan
$\text { By symmetry } \quad \mathrm{T}_{\mathrm{H}}=\mathrm{T}_{\mathrm{B}}$
$\mathrm{T}_{\mathrm{C}}=\mathrm{T}_{\mathrm{E}}$
$\Rightarrow$ Points $\mathrm{B}$ and $\mathrm{H} \& \mathrm{E}$ and $\mathrm{C}$ coule
ai ned toget her.
olving it like normal current circuit
Temp. difference across $\mathrm{BC}$
$\frac{{{{100}^ \circ } - {0^ \circ }C}}{{\frac{{7R}}{2}}} \times \frac{{5R}}{2} = \frac{{100}}{7} \times 5 = \frac{{500}}{7}{\,^ \circ }C$
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| Colum $I$ | Colum $II$ |
| $(A)$ Change in velocity | $(p)$ $-5 / 3\,Sl$ unit |
| $(B)$ Average acceleration | $(q)$ $-20\,SI$ unit |
| $(C)$ Total displacement | $(r)$ $-10\,SI$ unit |
| $(D)$ Acceleration at $t=3\,s$ | $(s)$ $-5\,SI$ unit |
