Question
Find the $10^{\text {th }}$ term of the AP $2,7,12, \ldots$
✓
Answer
Here $a = 2$;
$d = 7 - 2 = 5$.
So, $a_{10}=a+9 d=2+9 \times 5=47$
$d = 7 - 2 = 5$.
So, $a_{10}=a+9 d=2+9 \times 5=47$
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