Question
Find the additive inverse of:
$\frac{1}{-6}$

Answer

$\frac{1}{-6}=\frac{1\times(-1)}{-6\times(-1)}=\frac{-1}{6}$
$\therefore$ Additive inverse of $\frac{-1}{6}=-\Big(-\frac{1}{6}\Big)$
$=\frac{1}{6}$

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