Question
Find the angle which is equal to its supplement
✓
Answer
Let the angle be $x$.
Therefore, its supplement be $180^{\circ}-x$.
Since, the angle is equal to its supplement.
$
\therefore x=180^{\circ}-x
$
On transposing $x$ from RHS to LHS, we get
$
x+x=180^{\circ} \Rightarrow 2 x=180^{\circ}
$
On dividing both sides by 2 , we get
$
\therefore\frac{2 x}{2}=\frac{180^{\circ}}{2}=90^{\circ}
$
Hence, the required angle is $90^{\circ}$.
Therefore, its supplement be $180^{\circ}-x$.
Since, the angle is equal to its supplement.
$
\therefore x=180^{\circ}-x
$
On transposing $x$ from RHS to LHS, we get
$
x+x=180^{\circ} \Rightarrow 2 x=180^{\circ}
$
On dividing both sides by 2 , we get
$
\therefore\frac{2 x}{2}=\frac{180^{\circ}}{2}=90^{\circ}
$
Hence, the required angle is $90^{\circ}$.
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