Question
Find the angular separation between the consecutive bright fringes in a Young's double slit experiment with blue$-$green light of wavelength $500\ nm$. The separation between the slits is $2.0 \times 10^{-3}m.$
✓
Answer
Given that, $\lambda=500\text{nm}=500\times10^{-9}\text{m}$ and $d = 2 \times 10^{-3}m$
As shown in the figure, angular separation $\theta=\frac{\beta}{\text{D}}=\frac{\lambda\text{D}}{\text{dD}}=\frac{\lambda}{\text{d}}$
So, $\theta=\frac{\beta}{\text{D}}=\frac{\lambda}{\text{d}}=\frac{500\times10^{-9}}{2\times10^{-3}}=250\times10^{-6}$
$= 25 \times 10^{-5}$ radian
$= 0.01$4 degree.
As shown in the figure, angular separation $\theta=\frac{\beta}{\text{D}}=\frac{\lambda\text{D}}{\text{dD}}=\frac{\lambda}{\text{d}}$
So, $\theta=\frac{\beta}{\text{D}}=\frac{\lambda}{\text{d}}=\frac{500\times10^{-9}}{2\times10^{-3}}=250\times10^{-6}$
$= 25 \times 10^{-5}$ radian
$= 0.01$4 degree.
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