Question
Find the area enclosed by the curve $\text{y}=\sin\text{x}$ and the X-axis between $\text{x}=0$ and $\text{x}=\pi.$

Answer

$\text{Area}=\int\limits^{\text{y}}_{0}\text{dy}=\int\limits^{\pi}_0\sin\text{x dx}=-[\cos\text{x}]^\pi_0=2$

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