Question
Find the area of a rectangular park which is $41\frac{2}{3}\text{m}$ long and 18
✓
Answer
Length of rectangular field (l)
$=41\frac{2}{3}\text{m}=\frac{125}{3}\text{m}$
Breadth (b) $=18\frac{3}{5}\text{m}=\frac{93}{5}\text{m}$
$\therefore$ Area = l × b
$=\frac{125}{3}\times\frac{93}{5}\text{m}^2$
$=25\times31\text{m}^{2}=775\text{m}^2$
$=41\frac{2}{3}\text{m}=\frac{125}{3}\text{m}$
Breadth (b) $=18\frac{3}{5}\text{m}=\frac{93}{5}\text{m}$
$\therefore$ Area = l × b
$=\frac{125}{3}\times\frac{93}{5}\text{m}^2$
$=25\times31\text{m}^{2}=775\text{m}^2$
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