Question
Find the area of the triangle whose vertices are $(-2,6),(3,-6)$ and $(1,5)$.

Answer

Let $\Delta$ be the area of the triangle then,
$\Delta=\frac{1}{2}\left|\begin{array}{ccc}-2 & 6 & 1 \\ 3 & -6 & 1 \\ 1 & 5 & 1\end{array}\right|$
$=\frac{1}{2}|-2(-6-5)-6(3-1)+1(15+6)|$
$=15.5 \text { sq. units }$

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