Question
Find the base of a triangle whose are is $90 \mathrm{~cm}^2$ and height $12\ cm.$
✓
Answer
Area of triangle = $90 \mathrm{~cm}^2$
and height $(h) = 12\ cm$
$\therefore\text{Base}=\frac{\text{Area}\times2}{\text{Height}}$
$=\frac{90\times2}{12}=15\text{cm}$
and height $(h) = 12\ cm$
$\therefore\text{Base}=\frac{\text{Area}\times2}{\text{Height}}$
$=\frac{90\times2}{12}=15\text{cm}$
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