Question
Find the capacity of a closed rectangular cistern whose length is $8\ m$, breadth $6\ m$ and depth $2.5\ m$. Also, find the area of the iron sheet required to make the cistern.
✓
Answer
Length of the cistern,$ l = 8m$
Breadth of the cistern, $b = 6m$
Height (or depth) of the cistern, $h = 2.5m$
$\therefore$ Capacity of the cistern
= Volume of the cistern
$= l \times b \times h$
$= 8 \times 6 \times 2.5$
$= 120m^3$
Also,
Area of the iron sheet required to make the cistern
= Total surface area of the cistern
$= 2(lb + bh + hl)$
$= 2(8 \times 6 + 6 \times 2.5 + 2.5 \times 8)$
$= 2 \times 83$
$= 166m^2$
Breadth of the cistern, $b = 6m$
Height (or depth) of the cistern, $h = 2.5m$
$\therefore$ Capacity of the cistern
= Volume of the cistern
$= l \times b \times h$
$= 8 \times 6 \times 2.5$
$= 120m^3$
Also,
Area of the iron sheet required to make the cistern
= Total surface area of the cistern
$= 2(lb + bh + hl)$
$= 2(8 \times 6 + 6 \times 2.5 + 2.5 \times 8)$
$= 2 \times 83$
$= 166m^2$
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