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PROBABILITY — MATHS STD 11 Science — Question

Gujarat BoardEnglish MediumSTD 11 ScienceMATHSPROBABILITY1 Mark
MCQ
Find the center-radius form of the equation of the circle with center $(4,0)$ and radius 7 :
  • ✓
    $(x-4)^2+y^2=49$
  • B
    $x^2+(y+4)^2=7$
  • C
    $x^2+(y-4)^2=7$
  • D
    $(x+4)^2+y^2=49$
✓

Answer

Correct option: A.
$(x-4)^2+y^2=49$
  1. $(x-4)^2+y^2=49$
Solution:
If $(-g,-f)$ is the center and rr is radius
The $(x+g)^2+(y+f)^2=r^2$ is the equation of the circle There
$=C=(4,0), r=7$
$\Rightarrow(x-4) 2+(y-0) 2=72$
$=(x-4)^2+(y)^2=49$

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