Question
Find the continues products:
$(x-3)(x+3)\left(x^2+9\right)$
$(x-3)(x+3)\left(x^2+9\right)$
✓
Answer
$(x-3)(x+3)\left(x^2+9\right)$
$=\left\{(x)^2-(3)^2\right\}\left(x^2+9\right)$
$=\left(x^2-9\right)\left(x^2+9\right)$
$=\left(x^2\right)^2-(9)^2$
$=x^4-81$
$=\left\{(x)^2-(3)^2\right\}\left(x^2+9\right)$
$=\left(x^2-9\right)\left(x^2+9\right)$
$=\left(x^2\right)^2-(9)^2$
$=x^4-81$
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