MCQ
Find the correct option
- A$NH_3 < NF_3$ (Dipole moment)
- ✓$CO < CO_2$ [ $C-O$ bond length]
- C$NH_2^-> NH_4^+$ (Bond angle)
- D$I_3^-< N_3^-$ [lone pair of electron]
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[Given $: R =8.31 \,J \,K ^{-1} \,mol ^{-1}, \log 1.33=0.1239$ $\ln 10=2.3]$
$N{O_{\left( g \right)}} + \frac{1}{2}{O_2}_{\left( g \right)} \rightleftharpoons N{O_2}_{\left( g \right)}$
Given : $\Delta G^o_f (NO_2) = 52.0\, KJ/mole$
$\Delta G^o_f (NO) = 87.0\, KJ/mole$
$\Delta G^o_f (O_2) = 0\, KJ/mole$
$\mathop C\limits_6 {H_3} - \mathop C\limits_5 H = \mathop C\limits_4 H - \mathop C\limits_3 {H_2} - \mathop C\limits_2 \equiv \mathop C\limits_1 H$
The state of hybridization of carbons $1, 3$ and $5$ are in the following sequence