In the hydrocarbon, C _6 H_3 - C _5 H = C _4 H - C _3 H_2 - C _2 C _1 H The state of hybridization of carbons 1, 3 and 5 are in the following sequence

In the hydrocarbon, C _6 H_3 - C _5 H = C _4 H - C _3 H_2 - C _2 …

MCQ

In the hydrocarbon,

$\mathop C\limits_6 {H_3} - \mathop C\limits_5 H = \mathop C\limits_4 H - \mathop C\limits_3 {H_2} - \mathop C\limits_2 \equiv \mathop C\limits_1 H$

The state of hybridization of carbons $1, 3$ and $5$ are in the following sequence

A
$sp, sp^2, sp^3$
B
$sp^3, sp^2, sp$
C
$sp^2, sp, sp^3$
✓
$sp, sp^3, sp^2$

✓

Answer

Correct option: D.

$sp, sp^3, sp^2$

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