Question
Find the cube of:
$\frac{12}{7}$
$\frac{12}{7}$
✓
Answer
$\because\Big(\frac{\text{m}}{\text{n}}\Big)^3=\frac{\text{m}^3}{\text{n}^3}$
$\therefore\Big(\frac{12}{7}\Big)^3$
$=\frac{12^3}{7^3}$
$=\frac{12\times12\times12}{7\times7\times7}$
$=\frac{1728}{343}$
$\therefore\Big(\frac{12}{7}\Big)^3$
$=\frac{12^3}{7^3}$
$=\frac{12\times12\times12}{7\times7\times7}$
$=\frac{1728}{343}$
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