Question
Find the cube roots of these numbers : $\sqrt[3]{64}=$
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Answer
$\sqrt[3]{64}$
$\begin{array}{l}64=(2 \times 2 \times 2) \times(2 \times 2 \times 2) \\ =2^3 \times 2^3 \\ =(2 \times 2)^3=4^3 \\ \therefore \sqrt[3]{64}=4\end{array}$
$\begin{array}{l}64=(2 \times 2 \times 2) \times(2 \times 2 \times 2) \\ =2^3 \times 2^3 \\ =(2 \times 2)^3=4^3 \\ \therefore \sqrt[3]{64}=4\end{array}$
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