MCQ
Find the current in the loop.


- A$2/3\, A$
- B$5/3\, A$
- ✓$7/3\, A$
- DNone

then $I = \frac{{{E_{net}}}}{{{R_{net}}}} = \frac{{60 - 25}}{{15}} = \frac{{35}}{{15}} = \frac{7}{3}\,{\mkern 1mu} A$
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